1/6x^2-1/8x=1

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Solution for 1/6x^2-1/8x=1 equation: 


x in (-oo:+oo)

(1/6)*x^2-((1/8)*x) = 1 // - 1

(1/6)*x^2-((1/8)*x)-1 = 0

(1/6)*x^2+(-1/8)*x-1 = 0

1/6*x^2-1/8*x-1 = 0

DELTA = (-1/8)^2-(-1*1/6*4)

DELTA = 131/192

DELTA > 0

x = ((131/192)^(1/2)+1/8)/(1/6*2) or x = (1/8-(131/192)^(1/2))/(1/6*2)

x = 3*((131/192)^(1/2)+1/8) or x = 3*(1/8-(131/192)^(1/2))

x in { 3*(1/8-(131/192)^(1/2)), 3*((131/192)^(1/2)+1/8) }

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